What would three points on a graph be, graphing the x and y intercepts, with the equation -x + 3y = -9?

The x and y intercepts are what you get when plugging in y=0 or x=0. For a third point, you can choose any other x or y value you want and compute the other coordinate

To find the x-intercept, we can set y equal to zero in the equation -x + 3y = -9.

Plugging in y = 0, we get:

-x + 3(0) = -9.

Simplifying further:

-x + 0 = -9,

-x = -9,

x = 9.

Therefore, the x-intercept is (9, 0).

To find the y-intercept, we can set x equal to zero in the equation -x + 3y = -9.

Plugging in x = 0, we get:

-0 + 3y = -9.

Simplifying further:

3y = -9,

y = -9/3,

y = -3.

Therefore, the y-intercept is (0, -3).

To find a third point on the graph, we can choose any value for either x or y and compute the other coordinate using the equation -x + 3y = -9.

For example, let's choose x = -1.

Substituting x = -1 into the equation, we get:

-(-1) + 3y = -9.

Simplifying further:

1 + 3y = -9,

3y = -10,

y = -10/3.

Therefore, another point on the graph is (-1, -10/3).

So the three points on the graph, graphing the x and y-intercepts, with the equation -x + 3y = -9, are:

(9, 0), (0, -3), and (-1, -10/3).