Posted by Emma on Wednesday, July 11, 2007 at 4:18am.
solve the following pair of simultaneous equation:
can someone help please?i have no idea how to solve it =(
x/(ab) + y/b^2 = 1/b
x/(ab) + y/a^2 = 1/a
Subtract one from the other
y(1/b^2 - 1/a^2) = 1/b - 1/a
y(1/b + 1/a)(1/b - 1/a) = (1/b - 1/a)
Divide both sides by (1/b - 1/a)
y = 1/(1/a + 1/b)= ab/(a+b)
Now substitute this y into an earlier equation solve for x. I get x = y
Answer This Question
More Related Questions
- maths - solve the following pair of simultaneous equations. 2x-3y=13 3x+y=3
- maths - helo sir/madam can u help me to solve this problem solve the following ...
- maths - Solve the following simultaneous equation: 8x+3y=23 6x+5y=9
- maths - solve the following simultaneous equation: 5x+2y=29 x-y=-4 2x-y=-1 3x-y=...
- Maths - Can you pliz help me solve the following simultaneous equation 3x-y=2 ...
- maths - solve the following simultaneous linear equation: -5x+6y=44 9x+7y=-8
- Maths - Solve the following simultaneous equation by substitution method 5x+y=35...
- Mathematics - How do i solve the pair of simultaneous equations y=x^2-3x-12 and ...
- System of equations - 3x =2y = 17 2x-y =9 and 3x+y = 3 x+2y = -4 How do I do ...
- math algebra - COULD SOME OF WITH DEGREE IN MATHS HELP ME TO SOLVE THIS ...