Saturday
October 25, 2014

Homework Help: Maths

Posted by Emma on Wednesday, July 11, 2007 at 4:18am.

solve the following pair of simultaneous equation:

(x/a)+(y/b)=1
(x/b)+(y/a)=1

can someone help please?i have no idea how to solve it =(

x/(ab) + y/b^2 = 1/b
x/(ab) + y/a^2 = 1/a
Subtract one from the other
y(1/b^2 - 1/a^2) = 1/b - 1/a
y(1/b + 1/a)(1/b - 1/a) = (1/b - 1/a)
Divide both sides by (1/b - 1/a)
y = 1/(1/a + 1/b)= ab/(a+b)
Now substitute this y into an earlier equation solve for x. I get x = y

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

maths - solve the following pair of simultaneous equations. 2x-3y=13 3x+y=3
maths - helo sir/madam can u help me to solve this problem solve the following ...
maths - Solve the following simultaneous equation: 8x+3y=23 6x+5y=9
maths - solve the following simultaneous equation: 5x+2y=29 x-y=-4 2x-y=-1 3x-y=...
Maths - Can you pliz help me solve the following simultaneous equation 3x-y=2 ...
maths - solve the following simultaneous linear equation: -5x+6y=44 9x+7y=-8
maths pls help - 1. Solve the following simultaneous equations: log2 xy = 7 log2...
math - how do you solve that pair of simultaneous equation^2=4-y x=y+3?
math - how do you solve that pair of simultaneous equation^2=4-y x=y+3?
math - how do you solve that pair of simultaneous equation^2=4-y x=y+3?

Search
Members