# Maths

posted by
**Emma** on
.

solve the following pair of simultaneous equation:

(x/a)+(y/b)=1

(x/b)+(y/a)=1

can someone help please?i have no idea how to solve it =(

x/(ab) + y/b^2 = 1/b

x/(ab) + y/a^2 = 1/a

Subtract one from the other

y(1/b^2 - 1/a^2) = 1/b - 1/a

y(1/b + 1/a)(1/b - 1/a) = (1/b - 1/a)

Divide both sides by (1/b - 1/a)

y = 1/(1/a + 1/b)= ab/(a+b)

Now substitute this y into an earlier equation solve for x. I get x = y