math, bobpursley
posted by student on .
so how did you say to do part c
c) if there is 2 woman and 5 men in the group, how many delegations would include at least 1 woman?
would it be the answer to part a minus the number of 2 man pairs which will give me:
21  5combination 2 = 2110 = 11
Ooops, you are right.
7!/5!2!
sorry
So how do i find part A:
A group of 7 workers decide to send a delegation fo 2 to their superviosr to discuss their grievances.
a) how many delegations are possible?
this was my answer: 21
and you said was wrong....what do i have to do....
yes. You can work it by figuring the possibility of one woman, and two women, but it is easier to figure the men.
How i am getting confused...

a) 7*6*5*4*3*2*1/5*4*3*2*1=7*6=42 possiilites
b) 1*6=6 possible combinations
c) 22 possibilites