posted by Danica on .
In an election of two candidates the successful candidate secured 236 votes more than his rival.If the rival candidate obtained 1/6th of the total votes secured by the successful one in addition to his own votes, he would have won the elections by 42 votes. Find the number of votes secured by each candidate.
Let total no. of votes be 2x.
x+42 = (x/3)+(2x-236)
you can work it out for yourself (: