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September 18, 2014

September 18, 2014

Posted by **Diana** on Wednesday, June 27, 2007 at 9:52pm.

That doesn't sound possible.

If the sides of a square are increased, the area must also be increased.

Ms.Sue is correct. You may have copied down the problem incorrectly.

If increasing the sides by three INCREASES the area by 36, and the orginal side length is a, then

(a+3)^2 = a^2 + 36

a^2 + 6x + 9 = a^2 + 36

Subtract out the a^2 terms on both sides.

6x = 27

x = 4.5

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