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December 20, 2014

December 20, 2014

Posted by **Camila** on Monday, June 25, 2007 at 8:51pm.

1. y=x^2 - 2mx + (2m + 3)

2. D= b^2 - 4ac

3. D= (-2m)^2 - 4(1)(2m - 3)

4. 4m^2 - 8m + 12

5. 4(m^2 - 2m + 3)

6. 4(m + 1)(m - 3)

m (> or = to) 3, m (< or = to) -1

Then you draw the parabola with the roots -1 and 3 and shade the outside positive regions.

This problem is about finding out for which m the function:

y=x^2 - 2mx + (2m + 3)

has two zeros. This is the case if and only if D > 0.

If D > O, then why would m be > or = and not just >?

you are correct. If D>zero, it has two roots, and m >0 for two distinct roots.

OK, thanks! I was really confused with the whole problem! Thank you both for your help.

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