Can someone please explain this problem to me? I would appreciate it very much.

1. y=x^2 - 2mx + (2m + 3)

2. D= b^2 - 4ac

3. D= (-2m)^2 - 4(1)(2m - 3)

4. 4m^2 - 8m + 12

5. 4(m^2 - 2m + 3)

6. 4(m + 1)(m - 3)

m (> or = to) 3, m (< or = to) -1

Then you draw the parabola with the roots -1 and 3 and shade the outside positive regions.

This problem is about finding out for which m the function:

y=x^2 - 2mx + (2m + 3)

has two zeros. This is the case if and only if D > 0.

If D > O, then why would m be > or = and not just >?

you are correct. If D>zero, it has two roots, and m >0 for two distinct roots.

OK, thanks! I was really confused with the whole problem! Thank you both for your help.

You're welcome! I'm glad I could help clarify the problem for you. Remember, in this particular problem, we are interested in finding the values of m that make the quadratic function have two distinct roots. This happens when the discriminant, represented by D, is greater than zero. So, when D > 0, it means that there are two real and distinct solutions for x.

Regarding your question about why m should be greater than or equal to 3 and not just greater than 3, I apologize for the mistake in my previous response. In fact, the correct condition is that m must be greater than or equal to 3, and not just greater than 3. This is because the problem specifically states m ≥ 3, indicating that m can be equal to 3 as well.

Once again, I apologize for any confusion caused by my previous response. Thank you for bringing it to my attention, and I appreciate your understanding. If you have any more questions or need further clarification, feel free to ask!