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March 26, 2015

March 26, 2015

Posted by **dave** on Monday, June 25, 2007 at 12:42am.

Set the centripetal acceleration V^2/(R+h) equal to the gravitational acceleration, g * [R/(R+h)]^2

Then solve for V

R is the earth's radius and h is the 400 mile height. g is the acceleration of gravity at the earth's surface. It decreases with distance^2 from the center of the Earth. I suggest using metric units.

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