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September 1, 2014

September 1, 2014

Posted by **drwls** on Friday, June 22, 2007 at 9:54pm.

Solve y = x^2+ 2x- 8 = 0

You can write that as

y = (x+4) (x-2) = 0

There are two places where y = 0. The factored equation tells you where they are.

how would I find the x-intercepts of

y=x^2+2x-8

and

y=x^2-5x-10

thank you, I'm really having trouble getting this.

y = x^2-5x-10 does not factor easily.

If you solve x^2-5x-10 = 0 with the quadratic equation, you get

y = [5 +/- sqrt 65]/2

= +6.531 and -1.531

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