Posted by **Ace** on Monday, June 18, 2007 at 4:16pm.

Determine the convergence of the following series using the nth-partial sum or geometric series formula.

The sum of n=1 to inifitiy 1/(9n^2+3n-2)

How do I start? I'm guessing I should factor out the denominator but whats after that?

It is close to a geometric series, so use that test: the ratio of sucessive terms.

ratio= (9n^2+3n-2)/(9(n+1)^2 + 3(n+1) + 2)

and show it is less than one.

if it is geometric what is the sum of n?

## Answer This Question

## Related Questions

- sum geometric series - what is the sum of geometric infinite series 3/2+ 9/16+ ...
- Pre-Calculus - Q.Determine the sum of each infinite geometric series. t_1= 8 r...
- CALC 2 - a. Consider the following limit as a fact: lim n-> infinity ((n!)^1/...
- Math....Please help I have a deadline for tonight! - Use the geometric sequence ...
- Algebra - Use the geometric sequence of numbers 1, 1/3, 1/9, 1/27… to find the ...
- calc. - find the sum of the series of (-2)^n/3^n+1. This is an alternating ...
- Calc II - Use the comparison or limit comparison test to decide if the following...
- Calc - We are working on finding the intervals of convergence of power series in...
- Algebra - Two questions I need help with. Find the indicated partial sum using ...
- calculus - determine whether the series is convergent if so find sum it is the ...

More Related Questions