# Calculus

posted by
**COFFEE**
.

The hemispherical tank shown is full of water. Given that water weighs 62.5 lb/ft3, find the work required to pump the water out of the tank.

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What is shown is just the tank (a hemisphere) with a radius of 5 ft.

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First I calculated the Volume of the hemisphere, V = (2/3)*pi*r^3

V = (2/3)*pi*125 = (250/3)*pi

Then I took the integral of: Volume*5y*dy from 0 to 5.

Which equals: ((250/3)*pi)*(5/2)y^2 evaluated at 5 and 0.

I came up with 16362.5 ft*lb.

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Am I using the wrong method?