Posted by **COFFEE** on Sunday, June 17, 2007 at 5:47pm.

The hemispherical tank shown is full of water. Given that water weighs 62.5 lb/ft3, find the work required to pump the water out of the tank.

----------

What is shown is just the tank (a hemisphere) with a radius of 5 ft.

----------

First I calculated the Volume of the hemisphere, V = (2/3)*pi*r^3

V = (2/3)*pi*125 = (250/3)*pi

Then I took the integral of: Volume*5y*dy from 0 to 5.

Which equals: ((250/3)*pi)*(5/2)y^2 evaluated at 5 and 0.

I came up with 16362.5 ft*lb.

----------

Am I using the wrong method?

## Answer this Question

## Related Questions

- Calculus - The hemispherical tank shown is full of water. Given that water ...
- Calculus - The tank shown is full of water. Given that water weighs 62.5 lb/ft3...
- calculus - Calculate the work (in joules) required to pump all of the water out ...
- Calculus - A cylindrical water tank has a radius of 2 feet and a height of 6.0 ...
- Calculus - The tank shown is full of water. Given that water weighs 62.5 lb/ft3...
- Physics - Assume you construct a new water tower for a town water supply. Assume...
- Calculus - An inverted conical tank is 3m tall and 1m in diameter at its widest...
- Calculus - An inverted conical tank is 3m tall and 1m in diameter at its widest ...
- Calculus - An inverted conical tank is 3m tall and 1m in diameter at its widest...
- calculus(work) - a rectangular water tank has a length 20 ft, width 10 ft , and ...