Saturday

October 25, 2014

October 25, 2014

Posted by **COFFEE** on Sunday, June 17, 2007 at 5:47pm.

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What is shown is just the tank (a hemisphere) with a radius of 5 ft.

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First I calculated the Volume of the hemisphere, V = (2/3)*pi*r^3

V = (2/3)*pi*125 = (250/3)*pi

Then I took the integral of: Volume*5y*dy from 0 to 5.

Which equals: ((250/3)*pi)*(5/2)y^2 evaluated at 5 and 0.

I came up with 16362.5 ft*lb.

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Am I using the wrong method?

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