Friday

November 28, 2014

November 28, 2014

Posted by **Fonda** on Friday, June 15, 2007 at 4:27pm.

0.08,0.16,0.18,0.20,0.22,0.25,0.27,0.27,0.28,0.32

Q1; 0.16+0.18=0.34÷2=0.17

Q3; 0.27+0.28=0.55÷2=0.275(.28)

A. 0.18;0.27

B. 0.18; 0.28

C. 0.16; 0.28

D. 0.16; 0.27

What have I done wrong?

The data set is even, so the median is the average of #5 and #6. Median is .23

Then the first quartile is the middle value of the lower set, .18

The third quartile stops at the middle of the upper half, or .27

Answer A.

Now I have to warn you, various texts define the quartiles differently, there is no uniform agreement on this. Go with your text.

The data set is even, so the median is the average of #5 and #6. Median is .23

Then the first quartile is the middle value of the lower set, .18

The third quartile stops at the middle of the upper half, or .27

Answer A.

Now I have to warn you, various texts define the quartiles differently, there is no uniform agreement on this. Go with your text.

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