Wednesday
August 27, 2014

Homework Help: thermodynamics

Posted by jody on Friday, June 15, 2007 at 8:45am.

3.4 A heat engine operates between two heat reservoirs with temperatures of 560 and 280 K
a) The heat engine itself has a temperature of 560 K during heat addition from the 560 K
reservoir and a temperature of 280 K during heat rejection to the 280 K reservoir. The
thermal efficiency of the actual unit is 0.4, and the heat transfer rate from the 560 K
reservoir is 1000 kJ/min. Determine the entropy generation rate (kJ/min-K) for (1) the
heat engine itself, (2) the low temperature heat transfer process, and (3) the high
temperature heat transfer process. (.3572, 0, 0 kJ/K-min)
b) Now, for the same reservoir temperatures, heat transfer rate, and engine thermal
efficiency the engine itself receives heat at 540 K and rejects heat at 300 K. As before,
determine the entropy generation rate (kJ/min-K) for (1) the heat engine itself, (2) the
low temperature heat transfer process, and (3) the high temperature heat transfer process.
Which process has the largest irreversibility? (.148, .143, .0662 kJ/K-min)
c) Finally, for the same reservoir temperatures, heat transfer rate, and engine temperatures cited in part b) the thermal efficiency is increased to 0.42. For these conditions, determine the entropy generation rate for (1) the heat engine itself, (2) the low
temperature heat transfer process, and (3) the high temperature heat transfer process.
Which process now has the largest irreversibility? (.0814, .138, .0662 kJ/K-min)


We will be happy to critique your thinking or work on this. The question seems rather straighforward to me.

for part a I used thermal eff = Wout/Qh to find Wout. After that I used Qnet =Wnet.... Qin+Qout=Wout+Wbdry, where Wbdry is 0. and i solved for Q out. I then used Sgen = -((Qin/Thot)-(Qout/Tlow)) and I got .44 but the answer is .3572. Any words of wisdom?


I get .3572 for the a1, same numbers you did.
1000/560 - 400/280

i must be smoking crack..... thank you.i think i got the wrong answer about 5 times. I will try part b now.

For the second part of A. The only thing going on in the low temperature part is the rejection into the resivoir. there is no work being done. which then gives thermal eff = work /heat = o/600 = o. does that sound right or am i looking at this incorrectly?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physic II - a carnot heat engine operates between reservoirs at 550K and 300K, ...
HELP! Physics - A heat engine operates between two reservoirs at temperatures of...
Physics (Heat Engines) - 21. A heat engine operates in a cycle between ...
Physics - A reversible heat engine operates between thermal reservoirs at 1000 K...
physics - A Carnot engine is operated between two heat reservoirs at ...
physics - A Carnot engine is operated between two heat reservoirs at ...
thermodynamics - If a carnot engine receives heat from a heat source and ...
Physics, help! - A heat engine absorbs 126 kcal of heat and exhausts 77 kcal of...
physics - The maximum possible efficiency of a heat engine which exhaust its ...
physics - The maximum possible efficiency of a heat engine which exhaust its ...

Search
Members