Posted by **Katie** on Thursday, June 14, 2007 at 12:54am.

You are flying to the Moon. Find the point at which the gravitational attractions of Earth and Moon on you will be equal and opposite.

Given:

radius of the moon: 1.74*10^6 m

radius of the earth: 6.38*10^6 m

orbital radius of the moon: 3.8*10^8 m

Not enough information has been provided to answer that question. The point where gravitational attractions cancel out depends upon the relative MASSES of the Earth and Moon, bot the radii. Moon and earth have different average densities. You cannot deduce their relative masses from the relative radii.

Look up the relative masses of Earth and Moon. Call it M/m = a

Where the forces cancel, a = (d1/d2)^2

d1 is the distance to Earth and d2 is the distance to moon.

d1 + d2 = d1*(1+ 1/sqrt a)=3.8*10^8 m

## Answer This Question

## Related Questions

- physics - can you walk me through this problem At what distance from the Earth ...
- Physics - The Moon causes tides because the gravitational force it exerts ...
- Physics - Consider a space pod somewhere between earth and the moon, at just the...
- WSU PHY - The Moon causes tides because the gravitational force it exerts ...
- physics - Which of the following correctly describe the gravitational attraction...
- Physics - The average distance separating Earth and the Moon (center to center) ...
- physics - Suppose that the attraction between the moon and the earth were due to...
- Physics - When a spacecraft travels from the Earth to the Moon, both the Earth ...
- Physics - A. Use the relation 2 m m m GM g R ƒ to find the acceleration due to ...
- Physics - The orbital period of the moon about the earth is approximately 27.3 ...

More Related Questions