Posted by michelle on Wednesday, June 13, 2007 at 9:17pm.
How would you establish this identity:
on the right, sin^2 = 1-cos^2, that factor to 1-cos * `1+cos, then the denominator makes the entire right side 1+cosB
which is 1+1/sec which is 1/sec (sec+1)
using sec(beta) = 1/cos(beta):
1+sec(beta))/(sec(beta))= 1 + cos(beta)
1 + cos(beta)
This follows e.g. from:
(1 - x^2) = (1 - x)(1 + x)
(1 - x^2)/(1 - x) = 1 + x
- math - rahul, Thursday, April 25, 2013 at 11:54pm
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