Posted by **Tomika** on Wednesday, June 13, 2007 at 3:42pm.

Solve each of the following quadratic equations by completing the aquare.

1. x^2-6x-3=0

2. 2x^2+10x+11=0

Step 1.

Move the constant to the other side.

X^2 -6x + ?? = 3 + ??

To find ??, take 1/2 the x term and square it, then add it to both sides; therefore, 1/2*6 = 3 and 3^2 = 9.

X^2 -6x + 9 = 3 + 9

X^2 -6x + 9 = 12.

(X+3)^2 = 12

X+3 = sq rt 12

Solve for X. Post your work if you get stuck. The other one is worked the same way.

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