Posted by **Tomika** on Wednesday, June 13, 2007 at 3:22pm.

Find two consecutive positive integers such that the sum of the square is 85..(show your work)

If X is the first integer, then X+1 is the next; therefore, the sum of those squares will be 85.

X^2 + (X+1)^2 = 85

Solve for X, then add 1 to it for the second integer.

Post your work if you get stuck.

I am stuck that is why I posted on here for assistance..

I wrote the equation for you. The rest is just algebra. All you need to do is to solve for X. If you don't know how, tell me what you don't understand about the next step.

I was confused in where you said to add 1, would you still use the quadratic formula to solve the equation?

**If X is the first integer, then X+1 is the next; therefore, the sum of those squares will be 85.
**

X^2 + (X+1)^2 = 85

Solve for X, then add 1 to it for the second integer.
X^2 + X^2 + 2X + 1 = 85

2X^2 + 2X -84 = 0

Now use the quadratic formula.

You should get X = 6, then X+1 = 7 so the two integers are 6 and 7.

Thank you very much!!!

## Answer this Question

## Related Questions

- math, algebra - 2a+2ab+2b I need a lot of help in this one. it says find two ...
- Math - find three consecutive positive odd integers such that the sum of the ...
- algebra - Find two consecutive positive integers such that the sum of their ...
- math - there are three consecutive positive integers such that the sum of the ...
- Algebra - The difference of the cubes of two consecutive odd positive integers ...
- Algebra - The difference of the cubes of two consecutive odd positive integers ...
- algebra! - The difference of the cubes of two consecutive odd positive integers ...
- Algebra - The difference of the cubes of two consecutive odd positive integers ...
- college math - I do not understand a problem from a text book or how to solve ...
- math - the square of the sum of two consecutive positive even integer is greater...

More Related Questions