Solve for X.
x^2+4x+4=7 (Hint: Factor the left hand side)
I got stuck on this one, please help!!!Thanks in advance
Take the hint. Factor the left side.
(x+2)^2 = 7 Take square root of both sides.
x+2 = sq rt 7
etc .
To solve the equation x^2 + 4x + 4 = 7, you can start by factoring the left side of the equation using the "Hint" given.
The left side of the equation is a quadratic expression in the form of (x + a)^2, where a represents a constant.
So, we want to find a value for 'a' that would expand to give us the expression x^2 + 4x + 4 when squared.
To do this, we can take the coefficient of the 'x' term (which is 4) and divide it by 2, then square the result.
4 divided by 2 equals 2, and 2 squared equals 4.
Hence, we can rewrite the left side of the equation as (x + 2)^2.
Now, the equation becomes (x + 2)^2 = 7.
To solve for x, take the square root of both sides of the equation.
√((x + 2)^2) = √7
This simplifies to x + 2 = √7.
Finally, subtract 2 from both sides of the equation to isolate x.
x = √7 - 2
So, the solution to the equation x^2 + 4x + 4 = 7 is x = √7 - 2.