# Algebra

posted by
**jessica**
.

Hi I am learning about rational expression and so far I am pretty good at multiplying. My question is how do you divide?

Here is a problem that I am having trouble with..

6p-18 3p-9

----- / ----

9p p²+2p

This is what I have so far

6(p-3) 3(p-3)

------ / ------

9p p(p+2)

Can you show me what is next? Thanks.

You are OK so far.

[6(p-3)/(9p)]/{3(p-3)/[p(p+2)]} =

6(p-3) p(p+2)

------ x ------ =

9p 3(p-3)

[6/9] x [(p+2)/3] =

(2/9)(p+2)