Solve for x to the nearest hundreth and can you explain how you get your answer I don't understand

3^x = 1.295

Your question has nothing to do with trigonometry. You can solve for x by taking the logarithm (to any base) of both sides of the equation. Then
x log 3 = log 1.295
x = (log 1.295)/(log 3) = 0.2353..

To solve the equation 3^x = 1.295 to the nearest hundredth, we can follow these steps:

Step 1: Take the logarithm of both sides of the equation. The choice of logarithm base doesn't matter, as long as you use the same base for both sides. For simplicity, let's use the natural logarithm (base e) which is commonly denoted as ln.

Taking the natural logarithm of both sides:
ln(3^x) = ln(1.295)

Step 2: Use the logarithmic identity which states that ln(a^b) = b * ln(a). Applying this to the left side of the equation, we have:
x * ln(3) = ln(1.295)

Step 3: Divide both sides of the equation by ln(3) to solve for x:
x = ln(1.295) / ln(3)

Calculating the right side of the equation:
x ≈ 0.2353 (rounded to four decimal places)

Therefore, to the nearest hundredth, x is approximately 0.24.