Posted by
**Zam** on
.

A car travalling 90km/h, applies breaks with a force of 8400N to act on the 1050kg car.

a) what is the acceleration of the car when the breaks are applied?

b)how long does it take to stop.

c) how far does the car travel while it is breaking?

could anyone please help me with this, studying for exams and im not sure how to do this question.

F=ma or a=F/m

How long?

vfinal=vinit+ acceleration*time

notice acceleration is negative here.

How far?

distance=vinit*time + 1/2 a t^2

F=ma or a=F/m

How long?

vfinal=vinit+ acceleration*time

notice acceleration is negative here.

How far?

distance=vinit*time + 1/2 a t^2