Posted by **Zam** on Saturday, June 9, 2007 at 8:03pm.

A car travalling 90km/h, applies breaks with a force of 8400N to act on the 1050kg car.

a) what is the acceleration of the car when the breaks are applied?

b)how long does it take to stop.

c) how far does the car travel while it is breaking?

could anyone please help me with this, studying for exams and im not sure how to do this question.

F=ma or a=F/m

How long?

vfinal=vinit+ acceleration*time

notice acceleration is negative here.

How far?

distance=vinit*time + 1/2 a t^2

F=ma or a=F/m

How long?

vfinal=vinit+ acceleration*time

notice acceleration is negative here.

How far?

distance=vinit*time + 1/2 a t^2

## Answer this Question

## Related Questions

- Physics please help!! - A car starts from rest and travels for 5 seconds with a ...
- Physics - A car starts from rest and travels for 5.9 s with a uniform ...
- physics - A car starts from rest and travels for 5.3 s with a uniform ...
- physics - A car starts from rest and travels for 5.3 s with a uniform ...
- physics - A car starts from rest and travels for 6.0 s with a uniform ...
- Physics - A car starts from rest and travels for 5.4 s with a uniform ...
- physics - A car starts from rest and travels for 4.9 s with a uniform ...
- physics - a car moving on a straight road with a speed of 20m/s. at t=0 the ...
- physics - A car starts from rest and travels for 5.2 s with a uniform ...
- physics - A driver take 0.20 second to apply the breaks (reaction time). If he ...

More Related Questions