How would I find the vertex of the parabola y = x^2 – 2x + 4 ??

could some one explain the method to me ?

To find the vertex of a parabola in the form y = ax^2 + bx + c, you can use the following steps:

Step 1: Identify the coefficients in the equation.
In this case,
a = 1 (coefficient of x^2)
b = -2 (coefficient of x)

Step 2: Calculate the x-coordinate of the vertex using the formula -b / (2a).
For the given equation, x = -(-2)/(2*1) = 2/(2) = 1.

Step 3: Substitute the x-coordinate back into the equation to find the y-coordinate of the vertex.
Plug in x = 1 into the equation y = x^2 – 2x + 4:
y = (1)^2 – 2(1) + 4
y = 1 – 2 + 4
y = 3

Therefore, the vertex of the parabola y = x^2 – 2x + 4 is (1, 3).