How would I complete this problem?

Geometry. The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle.

I think the width is 3x+5 but not sure.


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Homework Help Forum: Algebra
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Posted by Loreal on Tuesday, June 5, 2007 at 4:25pm.
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How would I complete this problem?

Geometry. The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle.

I think the width is 3x+5 but not sure.

The area is the product of the length times the width or A = xy.

A is given as A = 3x^2 + 5x = xy

Dividing through by x yields y = 3x + 5.

To find the width of the rectangle, you can use the formula for the area of a rectangle, which is the product of the length and the width. In this case, the area is given as 3x^2 + 5x.

So, you can set up the equation A = lw, where A represents the area, l represents the length (x), and w represents the width.

Plugging in the given area, you have 3x^2 + 5x = lx.

To find the width, you need to solve for w or x in this case.

To do that, you can divide both sides of the equation by x:

(3x^2 + 5x)/x = x/x

This simplifies to:

3x + 5 = x

Now, you can isolate for x:

3x - x = -5

2x = -5

x = -5/2

So, the length of the rectangle is -5/2.

However, it is important to note that the length and width of a rectangle cannot be negative, so the value of x = -5/2 is not valid in this context.

Therefore, there may be an error in your initial assumption that the width is 3x + 5. I would recommend re-checking your calculations or seeking further advice from a teacher or tutor.