Monday
September 1, 2014

Homework Help: Algebra

Posted by Loreal on Tuesday, June 5, 2007 at 4:25pm.

How would I complete this problem?

Geometry. The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle.

I think the width is 3x+5 but not sure.


Subjects



Art



Business



Computers



English



Foreign Languages



Health



Home Economics



Mathematics



Music



Physical Education



Science



Social Studies







Features



Contribute



Download



Experts



Forum



Job Openings



Homework Tips



Libraries.Jiskha



Link to Us



Reference



School Supplies



Search







Homework Help Forum: Algebra
Current Questions | Post a New Question | Answer this Question | Further Reading

Posted by Loreal on Tuesday, June 5, 2007 at 4:25pm.
download mp3 free instrumental remix
How would I complete this problem?

Geometry. The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle.

I think the width is 3x+5 but not sure.

The area is the product of the length times the width or A = xy.

A is given as A = 3x^2 + 5x = xy

Dividing through by x yields y = 3x + 5.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

algebra , help - Can someone help me set up the equations thanks. Directions: ...
math117 - The area of a rectangle of length x is given by 3x2 +5x. Find the ...
Algebra/geometry - a rectangle has a width of 4 cm less than it's length. if a ...
math - a rectangle is twice as long as it is wide. if both of its dimensions are...
mat117/algebra - The area of a rectangle of length x is given by 3x^2 + 5x. Find...
algebra help please - The area of a rectangle of length x is given by 3x^2+5x ...
math - The length, l, of a rectangle is 2 feet less than three times the width, ...
math - The length of a rectangle is 5 in. more than twice its width.? How do I ...
pre-algebra - Can you help me figure this? The area of a rectangle is 14 square ...
basic geometry - A rectangle has width the same asa a side of a square whose ...

Search
Members