algebra 2
posted by Ray .
evaluate if possible
1. square root 121
A not a real number
2. 3cube8/27
would this be
3cube 2/3
number 1 is correct i've had that one in my homeworks previously.
number two i am not sure how it would actually look
3^3+ (8)/(27)= If so to reduce it I have to agree with your answer.
the square root of 121 is 11 ..
11 * 11 = 121
unless you mean NEGATIVE 121?

what is the remainder when (2x3  3x2  10x + 15) (x + 2)