The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle

let x = width
length is then 2x+4
so
2(2x+4)+2x=32
Solve for x
4x + 8 +2x = 32
6x=24
x=4

thanks

To find the width of the rectangle, we'll use the given information about the length and perimeter.

Let's assume that the width of the rectangle is represented by the variable "x". According to the problem, the length of the rectangle is 4 inches more than twice its width. This can be expressed as "2x + 4".

The perimeter of a rectangle is the sum of all its sides. In this case, the formula for the perimeter is: 2(length + width), which can be written as: 2(2x + 4 + x).

Now, we can set up an equation to solve for "x", the width of the rectangle.

2(2x + 4 + x) = 32

Simplifying the equation, we get:

4x + 8 + 2x = 32

Combining like terms, we have:

6x + 8 = 32

Subtracting 8 from both sides, we get:

6x = 24

Finally, dividing both sides by 6, we find:

x = 4

Therefore, the width of the rectangle is 4 inches.