# algebra

posted by
**veronica**
.

The length of a rectangle is 4 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle

let x = width

length is then 2x+4

so

2(2x+4)+2x=32

Solve for x

4x + 8 +2x = 32

6x=24

x=4

thanks