Posted by **alfred** on Sunday, June 3, 2007 at 5:04pm.

a baseball team a series of five games to play, with one game each day from monday through friday. If it rains on the day of a scheduled game, the game is cancelled. There is a 20 percent probability of rain each day. how likely is it that the team will get to play at least 2 of the five games?

50 % chance

To play "at least 2" of the 5 games, each day can be considered as having .2 probability of rain or .8 probability of not raining.

The probability of playing 2 of the five is

.2*.2*.2*.8*.8.

(To get the probability of

*all* events occurring, you

*multiply* the individual events.)

However, since it is "at least 2," you need to consider the probability of not raining on 3, 4 or 5 days.

Calculate those in the same manner as the first alternative.

Since they can play in any one

*or* another of these scenarios, you would

*add* the values found for those four scenarios to get your final probability.

It may or may not be .5. Regardless, at least now you should understand the process, so you deal with similar problems in the future.

I hope this helps. Thanks for asking.

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