Posted by **needhelpplease** on Saturday, June 2, 2007 at 9:44pm.

Can someone please help me with solving this equation (I don't know how to do it with the fractions)

1/3 x1^-2/3 . x2^2/3

--------------------

2/3 x1^1/3 . x2^-1/3

how do I cancel out some of the terms and reduce it down so that Im left with x2 on top and x1 on bottom??

And please explain it because I don't know how to cancel out with fractions.

Thanks xx

Add the fractions

a

^{b } * a

^{c }= a

^{b+c }
it probably doesnt show that well but one is x1 and the other x2 so you can add their fractions

## Answer This Question

## Related Questions

- math - how you multoply 5 2/7 x 5/8 x 3 1/2 write the answer in simplest form ...
- Algebra - Please check for me. 7p - 7/p divided by 10p-10/5p^2 = 7p^2 6x - 6/x...
- math - I need help solve the equation by fractions 8/(21-y) = 12/(y+19) I think ...
- pre-algebra - Solve the equation- w(-2)=14 m-7= -3 -3h= -42 Here are some basic ...
- Math - please explian this not sure about fractions thanks :) 1/3, 5/6 , and 3/8...
- Math - Simlifying Rational Expressions Reduce to lowest terms, stating the ...
- math - round 0.8394263 to the nearest hundred-thousndth. Add the fractions 2/3,3...
- Algebra - (3x^2+2)/(x^2-4)-(9x-x^2)/(x^2-4) Your problem: (3x^2+2)/(x^2-4)-(9x-x...
- Simplifying Rational Expressions - 1.4x12 / 4x 2.d+7 / d^2-49 3.t^2-25 / t^2+t-...
- Calculus - Series - Why is the limit of the sum n=1 to infinity of ln(2(n+1))â€“...

More Related Questions