# math

posted by
**Luke** on
.

what would x^2+y^2-4x+2y=0 (Equation for a cirlce) be in

r^2=(x-h)^2(y-k)^2 form?

tnx

I will start you off...

x^2+y^2-4x+2y=0

x^2-4x+y^2 +2y =0

x^2-4x+ 4 + y^2 +2y+ 4 =+ 4+ 4

(x^2-4x+ 4) + (y^2 +2y+ 4) =8