look at the chart- out of 150 dog owners 75 perfer human food only,45 perfer pet food only and 30 perfer both human and pet food.
So what percent of dog owners reported their dog likes either only human food or only pet food?
P(human food) = 75/150 = .5
P(pet food)= 45/150 = .3
or question so adding
P(humanfood)+P(petfood)
.5 + .3 = .8
80%
% = [part/total]*100.
human food only = [75/150]*100 = ??
pet food only = [45/150]*100 = ??
thanks for the help
To find the percentage of dog owners who reported their dog likes either only human food or only pet food, you need to add the probabilities of each preference together.
First, you need to find the probability of a dog liking human food only. This can be calculated by dividing the number of dog owners who prefer human food only (75) by the total number of dog owners (150). So, P(human food) = 75/150 = 0.5.
Next, you need to find the probability of a dog liking pet food only. This can be calculated by dividing the number of dog owners who prefer pet food only (45) by the total number of dog owners (150). So, P(pet food) = 45/150 = 0.3.
Finally, you can add the probabilities together to get the combined probability of a dog liking either human food only or pet food only. P(human food) + P(pet food) = 0.5 + 0.3 = 0.8.
To convert this into a percentage, you multiply by 100. So, the percentage of dog owners who reported their dog likes either only human food or only pet food is 0.8 * 100 = 80%.
In terms of the calculations for the specific preferences:
- The percentage of dog owners whose dogs like only human food is [75/150] * 100 = 50%.
- The percentage of dog owners whose dogs like only pet food is [45/150] * 100 = 30%.