Posted by **Emma** on Wednesday, May 30, 2007 at 9:20am.

a parabola with turning point at (1,-2) and passing through the origin.find the equation of this parabola.

how do i do this? can someone please show me how to solve it step by step?thanks!

You know that at x = 0 the function is zero. Because the turning point is at

x = 1 must be in the middle of the two zeros of the function, the other zero is at x = 2.

Therefore the function is of the form:

y = A(x - 0) (x - 2) = Ax(x-2)

Solve for A by demanding that at x = 1 y = -2

## Answer this Question

## Related Questions

- Algebra2/Trig - Find an equation of the parabola with vertex at the origin. ...
- Maths - Find the equation of a line which is perpendicular to 2x + 3y = 4 ...
- algebra 2 - Directions: The focus and directrix of a parabola are given. Write ...
- College Algebra - Find the standard form of the equation of the parabola with ...
- College Algebra - Find the standard form of the equation of the parabola with ...
- Pre-Algebra [urgent!] - I can't find the solution to this problem; can someone ...
- maths help needed!(urgent) - find the equation of the tangent to y=x-(a^3/x^2) ...
- Calculus - Find expressions for the quadratic functions whose graphs are shown. ...
- MATHS - a parabola passes through the points (1,1) , (2,0) and (3,1) the ...
- math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...