Posted by **Corin** on Wednesday, May 30, 2007 at 12:07am.

As a balloon in the shape of a sphere is being blown up, the radius is increasing 1/pi inches per second. At what rate is the volume increasing when the radius is 1 inch?

I know that the volume of a sphere = 4/3(pi)r^3

I don't know what to do next.

Figure dV/dt

dV/dr *dr/dt= dV/dt

you know the expression for dv/dr (take the derivative of V(r), and you are given dr/dt as 1/pi per sec.

## Answer this Question

## Related Questions

- calculus - 3. The radius r of a sphere is increasing at a constant rate of 0.04 ...
- math - RATES OF CHANGE QUESTION A spherical balloon is being blown up so that ...
- Calculus - Air is being pumped into a spherical balloon and the volume is ...
- math - Air is pumped into a balloon such that its volume increases at the rate ...
- calculus - A spherical balloon is being inflated at a rate of 10 cubic inches ...
- Calculus - A spherical balloon is being inflated at a rate of 10 cubic inches ...
- calculus - A spherical balloon is being inflated so that its volume is ...
- relaited rates - A spherical balloon is being inflated so that its volume is ...
- calculus - Air is being pumped into a spherical balloon so that its volume ...
- Calculus - Air is being pumped into a spherical balloon so that its volume ...