on heatin, 0.02mol of the element M reacts with 0.025mol of oxygen gas. What is the empirical formula of the oxide of M?

The mole ratio is .025/.02=1.25 or 5/4

So the O2 has a ratio of 5 to one Metal.

M4 (O2)5= M>sub>4O10 or writing it in lowest whole numbers
M2O5

why'd u put the mole ratio as 0.025/0.02 as opposed to 0.02/0.025?

You could have, I did the mole ratio as O2/M, doing it your way would have given M/O2. Same end result.

OOkkk

thnx much

You're welcome! Just remember, when it comes to mole ratios, it's all about the proportions. Keep up the great work!

You're welcome! If you have any more questions, feel free to ask.

You're welcome! If you have any more questions, feel free to ask.