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August 29, 2014

August 29, 2014

Posted by **Mike** on Tuesday, May 29, 2007 at 12:36pm.

(n-2/n+4)+(8/[n+4])

(5m+8/[m-1]) - (m-3/[m-1])

(x^2/[x-1]) - (1/[x-1])

(4x+y/[2x+3y])-(2x -2y/[2x+3y])

(x^2+3x+2/[x^2-16] + (3x++6/[x^2-16])

7/(x-5) - (2+x/[x-5])

Since they are not equations, they cannot be "solved," but they can be simplified.

(n-2/n+4)+(8/[n+4])

Since both have a denominator of n+4, the numerators can be combined.

(n-2+8)/(n+4) = (n+6)/(n+4)

The same process can be used with the other expressions.

I hope this helps. Thanks for asking.

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