Wednesday

July 30, 2014

July 30, 2014

Posted by **micole** on Tuesday, May 29, 2007 at 11:35am.

I started with using KE = (1/2)mv^2 and m1v1 = m2v2. Then (1/2)m1(v1)^2 + (1/2)m2(v2)^2 = 8000J. How do I find the velocities? I tried rearranging the equations to solve for one of the unknowns, but got stuck.

Momentum is conserved. The initial momentum is zero, therefore:

m1 v1 + m2 v2 = 0 ---->

m1 v1 = m2 v2 ----->

(m1 v1)^2 = (m2 v2)^2

1/2 m1 v1^2 = 1/2 m2 v2^2 * (m2/m1)

So, you have:

KE1 + KE2 = 8000 J

and:

KE1 = (m2/m1) KE2

**Related Questions**

p - An explosion breaks a 10 kg object (originally at rest) into two pieces, one...

Physics - An explosion breaks an object into two pieces, one of which has 2 ...

physics-collisions - An internal explosion breaks an object, initially at rest, ...

physics - A 41.0-kg body is moving in the direction of the positive x axis with ...

college physics - A 915 kg two-stage rocket is traveling at a speed of 5.50×10^3...

physics - A 14 kg body is moving through space in the positive direction of an x...

Physics - An isolated 3 kg object is moving in the positive y direction along ...

Physics - "A rocket with mass 1200kg reaches a speed of 300m/s when an explosion...

Physics - A stick of dynamite (190 g) contains roughly 10 J of chemical energy ...

Physics - A stick of dynamite (190 g) contains roughly 10 J of chemical energy ...