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March 28, 2015

March 28, 2015

Posted by **COFFEE** on Monday, May 28, 2007 at 9:33pm.

Integral of: [(x^3)*(1-x^4)^5]dx

Put 1-x^4 = y

Then -4x^3 dx = dy

Integral is then becomes:

Integral of -1/4 y^5 dy

ok, thanks a lot! I got it now.

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