Posted by Cody on .
I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?
The problem is 3y = 2x + 12
My Work:
0=2x+ 12

2 2
x=6
You cannot solve this equation. It has 2 unknowns.
I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?
The problem is 3y = 2x + 12
My Work:
0=2x+ 12 How and/or why did you eliminate y from the equation.

2 2
x=6
A ssuming you are seeking integer answers.
13y  2x = 12
2Dividing through by 2 yields y + y/2  x = 6
3y/2 must be an integer k mking y = 2k
4Substituting back into (1)0 yields 6k  2x = 12 making x = 3k  6
5CLearly, without any other conditions imposed by the problem statement, there are an infinite number of answers.
6k...0...1...2...3...4...5...6..
...x..6..3...0...3...6...9..12..
...y...0...2...4...6...8..10..12..
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Homework Help Forum: Math
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Posted by tchrwill on Monday, May 28, 2007 at 1:22pm in response to Math.
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I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?
The problem is 3y = 2x + 12
My Work:
0=2x+ 12 How and/or why did you eliminate y from the equation.

2 2
x=6
A ssuming you are seeking integer answers.
13y  2x = 12
2Dividing through by 2 yields y + y/2  x = 6
3y/2 must be an integer k making y = 2k
4Substituting back into (1) yields 6k  2x = 12 making x = 3k  6
5Clearly, without any other conditions imposed by the problem statement, there are an infinite number of answers.
6k...0...1...2...3...4...5...6..etc.
...x..6..3...0...3...6...9..12..etc.
...y...0...2...4...6...8..10..12..etc.
http://www.jiskha.com/display.cgi?id=1180111741
http://www.jiskha.com/display.cgi?id=1180111741

Math 
moose,
oh this is easy just...wait i have my own homework to do and i don't even know you

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