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October 25, 2014

October 25, 2014

Posted by **Cody** on Monday, May 28, 2007 at 11:10am.

The problem is 3y = 2x + 12

My Work:

0=2x+ 12

--------

2 2

x=6

You cannot solve this equation. It has 2 unknowns.

I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?

The problem is 3y = 2x + 12

My Work:

0=2x+ 12 How and/or why did you eliminate y from the equation.

--------

2 2

x=6

A ssuming you are seeking integer answers.

1--3y - 2x = 12

2--Dividing through by 2 yields y + y/2 - x = 6

3--y/2 must be an integer k mking y = 2k

4--Substituting back into (1)0 yields 6k - 2x = 12 making x = 3k - 6

5--CLearly, without any other conditions imposed by the problem statement, there are an infinite number of answers.

6--k...0...1...2...3...4...5...6..

...x..-6..-3...0...3...6...9..12..

...y...0...2...4...6...8..10..12..

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Homework Help Forum: Math

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Posted by tchrwill on Monday, May 28, 2007 at 1:22pm in response to Math.

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I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?

The problem is 3y = 2x + 12

My Work:

0=2x+ 12 How and/or why did you eliminate y from the equation.

--------

2 2

x=6

A ssuming you are seeking integer answers.

1--3y - 2x = 12

2--Dividing through by 2 yields y + y/2 - x = 6

3--y/2 must be an integer k making y = 2k

4--Substituting back into (1) yields 6k - 2x = 12 making x = 3k - 6

5--Clearly, without any other conditions imposed by the problem statement, there are an infinite number of answers.

6--k...0...1...2...3...4...5...6..etc.

...x..-6..-3...0...3...6...9..12..etc.

...y...0...2...4...6...8..10..12..etc.

http://www.jiskha.com/display.cgi?id=1180111741

http://www.jiskha.com/display.cgi?id=1180111741

- Math -
**moose**, Monday, January 5, 2009 at 9:23pmoh this is easy just...wait i have my own homework to do and i don't even know you

- woqlu ugzibq -
**woqlu ugzibq**, Saturday, January 17, 2009 at 1:56amyzqmu swonezhxg bywxh bgdvahl crhfkdeu ctpysream xzpv

- amwfs avgr -
**amwfs avgr**, Thursday, February 5, 2009 at 4:55amsgxkmqc omgfeyhw mwvsgfhc ezrvyc jesfpktqr hlzwp zavkm

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