Posted by **struggling** on Saturday, May 26, 2007 at 8:05pm.

Solve the system by addition or substitution.

16x-4y=20

y=4x-4

I ask for help with this and forgot to add the problem. can anyone help me understand how to do this?

16x-4y=20

-4x+y=-4

___________

16x-4y=20

(4)(-4x+y=-4)

______________

16x-4y=20

-16x+4y=-16

______________

0=4

answer: empty set

16x - 4(4x-4) = 20

16x - 16x - 16 = 20

-16 = 20

It doesn't work. Anonymous is right. Empty Set.

- algebra -
**Anonymous**, Monday, May 27, 2013 at 2:17pm
76-78

## Answer this Question

## Related Questions

Algebra - There are two solutions to | 16x - 5 | = 3. The greatest solution is ...

Math - 5(-3x - 2) - (x - 3) = -4(4x + 5) + 13 Answer Multiply factors. -15x - 10...

algebra - x^2 +16x+64 x^2+16x=64 (x=3)^2=16x-64 16x=-64 x=-4 Check this problem ...

Algebra 2 - (1/16x^4 +3/8x^3 +1/8x^2-1)+ (-9/16x^4 +7/8x^2 -1) Can you please ...

Algerbra - how do you solve 7(3x+4)=8(2x+5)+13 expand the parenthesis...I will ...

math - The question is (2x+1)^2-2(2x^2-1) in simplest form Is this correct? [(2x...

Pre-Calculus - Help please If f(x)=8x and g(x)=2x+1 find (fog)(x) 16x^2+8x 16x+1...

Algebra 2 - 16x^2+16y^2-16x+24y-3=0 How do I solve this?

algebra please help - 1/ 2/ 3x^2-22x-40 + 2/3x^2-16x + 20 add and simplify can ...

calculus - i need to find the derivative using chain rule: (x^2 + 2x - 6)^2 (1-x...