Posted by **struggling** on Saturday, May 26, 2007 at 8:05pm.

Solve the system by addition or substitution.

16x-4y=20

y=4x-4

I ask for help with this and forgot to add the problem. can anyone help me understand how to do this?

16x-4y=20

-4x+y=-4

___________

16x-4y=20

(4)(-4x+y=-4)

______________

16x-4y=20

-16x+4y=-16

______________

0=4

answer: empty set

16x - 4(4x-4) = 20

16x - 16x - 16 = 20

-16 = 20

It doesn't work. Anonymous is right. Empty Set.

- algebra -
**Anonymous**, Monday, May 27, 2013 at 2:17pm
76-78

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