# math/algebra1a

posted by
**Confused** on
.

Write the equation of the line passing through (-3, -5)and (3,0).

(a)y= -6/5x - 5/2

(b)y= 5/6x - 5/2

(c)y= 5/6 x + 2/5

(d)y= -6/5x + 2/5

You have to get the slope of the line using equation y2-y1/x2-x1.

[0-(-5)]/[3-(-3)] = 5/6

Now that you have the slope, you have to solve for the y-intercept. Use the x and y value from one of your coordinates to solve for b.

y = mx+b

0 = (5/6)(3) + b

0 = 5/2 + b

-5/2 = b

So your equation is y=5/6x - 5/2.