April 20, 2014

Homework Help: math/algebra1a

Posted by Confused on Saturday, May 26, 2007 at 6:25pm.

Write the equation of the line passing through (-3, -5)and (3,0).
(a)y= -6/5x - 5/2
(b)y= 5/6x - 5/2
(c)y= 5/6 x + 2/5
(d)y= -6/5x + 2/5

You have to get the slope of the line using equation y2-y1/x2-x1.

[0-(-5)]/[3-(-3)] = 5/6

Now that you have the slope, you have to solve for the y-intercept. Use the x and y value from one of your coordinates to solve for b.

y = mx+b
0 = (5/6)(3) + b
0 = 5/2 + b
-5/2 = b

So your equation is y=5/6x - 5/2.

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