Posted by **jessica** on Friday, May 25, 2007 at 4:28pm.

find the standard form of the equation of the ellipse with center (0,0) and foci at (+- 4square root 3, 0) and verticies (+-8,0)

x^2/a^2 + =y^2/b^2 = 1

a = 8

b = sqrt(8^2 - (4sqrt3)^2)

..= sqrt(64 - 48) = sqrt(16) = 4

Thus, x^2/64 + y^2/16 = 1

## Answer this Question

## Related Questions

- pre cal - find the standard form of the equation of a parabola with the vertex (...
- Pre-Cal - Find the standard form of the equation of the ellipse. (Remember ...
- Pre-calculus - For the ellipse with equation 5x^2+64y^2+30x+128y-211=0, find the...
- pre-calculus - the foci of an ellipse are (0,2) (0,-2) and the eccentricity is 1...
- pre cal - finding the standard form the center eccentricity vertices foci and ...
- College Algebra. - Find the equation in standard form of the ellipse, given ...
- Calculus - Write the equation of an ellipse with the foci (17, 0) and (-17, 0) ...
- Algebra 2 - How do I find the equation of an ellipse with: Vertices: (-7,10), (-...
- Pre-Calculus - I am having trouble with several problems: 1) Find the ...
- Pre-Calculus - I am having trouble with several problems: 1) Find the ...

More Related Questions