Monday

March 30, 2015

March 30, 2015

Posted by **Sandra** on Thursday, May 24, 2007 at 6:08pm.

6x^2-23x+15=0

6x^2-23x+15 = (a x + b) (c x + d) -->

a c = 6 (1)

a d + b c = -23 (2)

b d = 15 (3)

You could write down all possibilities for a and c (Eq. 1) and all possibilites for b and d (Eq. 3) and see which one satisfies Eq. 2

But there are 16 possibilities, so let's not do this. Instead let's take another look at Eq. 3. This equation is just saying that the factorization of the quadratic must be valid at x = 0!

So, perhaps we can simplify things by just demanding that the factorization must also be valid at another point, say, x = 1. For x = 1 the quadratic 6x^2-23x+15 equals -2. If we substitute x = 1 in (a x + b) (c x + d) we get

(a + b)(c + d). This means that:

(a + b)(c + d) = -2 (4)

So either:

a + b = -2 and c + d = 1 (5)

or

a + b = 2 and c + d = -1 (6)

Now a and c are factors of the number 6 as you can see from Eq. 1 while b and d are factors of 15 (Eq. 3).

You now only need a little trial and error to find the solution:

a= -1; b = 3; c= -6; d = 5, because that satisfies Eq. 6:

-1 + 3 = 2

-6 + 5 = -1

Note that if you expand out Eq. 4 and use Eq. 1 and Eq. 2, you get Eq. 2 so you don't have to check if Eq. 2 is satisfied. So you have obtained the factorization:

6x^2-23x+15 = (-x+3)(-6x+5).

it doesn't specify a method, so why not just use the formula

x=(23 ± √169)/12

x=(23 ± 13)/12

x = 3 or x= 5/6

**Answer this Question**

**Related Questions**

Discrete Math - Please help with this problem. Thanks a/ Show that for any real ...

Algebra - almost done with Algebra...help! 2 3x – 6(2x – 0.055) = 10x + 0.515 I ...

math - Have 2 questions: 1. Factor Trinomial competely x^2 + 8x + 53 (reads as x...

Math - One solution of 12x^3-23x^2-3x+2=0 is 2. Find all other solutions. I ...

math - question is 40x^2 + 23x -30 = 0 reads as 40x squared plus 23x minus 30 ...

Factoring Trinomials - Working on how to factor trinomials, and the method that ...

math - 6xsquared = 23x+18

calculus - Solve the equation in the real number system X^4+11x^3+24x^2-23x+35=0...

Algebra - use factoring to solve the equation 4x²-23x=6 I think the answer is x...

math - 6x (squared) = 23x+18 help please