Saturday
April 19, 2014

Homework Help: Algebra 2 once more

Posted by Lindsay on Wednesday, May 23, 2007 at 5:54pm.

I have more answers that I would like checked. Also, there is one that I'm really confused about. I appreciate any help. :)

Rewrite as the log of a single number.
1) 8 ln 2 = ln(2^8)
2) log 42 - log 6 = log 36 (I think this one may be wrong).

Evalute each expression w/o a calculator.
3) log(subscript 12) (superscript 5)square root of 12 = 0.2
4) log(subscript 6) 216 = 3

The one I'm not sure how to do looks like this: log(subscript 4)s^3 = 8. I'm supposed to solve for s. It would be great if someone could show me the steps for how to solve it.

#1 is right
#2, no
log A - log B = log (A/B)
so log 42 - log 6 = log 7

#4 is good

#5..... is this what you mean? (log12 √12)5 ?

if so, then you would have (1/2)^5
= 1/32

for log(subscript 4)s^3 = 8

4^8 = s^3
s^3 = 65536
s = appr. 40.317 (I took the cube root)


Actually, the 5 is before the square root symbol. I'm just not sure how to type it out...!

then my interpretation was right
remember that

log2 x is the same as (log x)2

Riiight ok I remember that now. Thanks again for the help. :)

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

BPC110 - Hello, I am trying to use APA format. I did some short answers and ...
Algebra - I have one more question I need to ask about algebra, this one is a ...
com170 - I believe this paragraph below is a Analysis I have to pick between ...
com 170 - I believe this paragraph below is a Analysis I have to pick between ...
english - Alice Axia’s article discussed overlooked tax deductions. It talked ...
English - Is this a summary?Alice Axia’s article discussed overlooked tax ...
com170 - Is this a summary, analysis, synthesis or evaluation 1. Alice Doe’s ...
com170 - Is this a summary, analysis, synthesis or evaluation 1. Alice Doe’s ...
Navigation - Thanks Damon for your help yesterday. I see now there are close ...
English - Lesson Objective Students can greet people whom they meet for the ...

Search
Members