Homework Help: calc

Posted by marsha on Wednesday, May 23, 2007 at 5:34pm.

also:

integral of tan^(-1)y dy

how is integration of parts used in that?

You write:

arctan(y)dy = d[y arctan(y)] -
y d[arctan(y)]

Here we again have used the product rule:

d(fg) = f dg + g df

You then use that:

d[arctan(y)] = 1/(1+y^2) dy

So, the integral becomes:

y arctan(y) - Integral of y/(1+y^2) dy

And:

Integral of y/(1+y^2) dy =

1/2 Log[1+y^2] + const.

No one has answered this question yet.

Answer this Question

Related Questions

calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...
calc - evaluate the integral: y lny dy i know it's integration by parts but ...
precal - The values of x that are solutions to the equation cos^(2)x=sin2x in ...
calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...
calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...
calculus - Now we prove Machin's formula using the tangent addition formula...
Math - Arrange these in order from least to greatest: arctan(-sqrt3), arctan 0, ...
PRE-CALC - sin(arctan(-4/3) okay so i made arctan(-4/3) = x so im solving for ...
Calculus - Pls help solve this problem if sqrt(y)=(arctan)tan-1(x), show that (1...
Maths - if sqrt(y)=(arctan)tan-1(x), show that (1+x^2)dy/dx((1+x^2)dy/dx)=2

For Further Reading

First Name:
School Subject:
Answer: