Algebra

posted by on .

I am stuck, pleas help, i have the example but I am still not able to figure it out...

Find the value of X...5/x+6+2/x^2+7x+6=3/X+1

Find the value of X...2/5=x-2/20

First, get the X terms on one side of the equation and the numbers on the other.

2/5=X-2/20

2/5+2/20 = X

Change the numbers to get a common denominator.

4/10+1/10 = X

Combine and reduce.

X = 5/10 = 1/2 = .5

5/x+6+2/x^2+7x+6=3/X+1

Get the X terms on one side of the equation and the numbers on the other.

5/X+2/X^2+7X-3/X = -11

Multiply both sides by X^2.

5X+2+7X^3-3X = -11X^2

Again, get the X terms on one side of the equation and the numbers on the other.

7X^3+11X^2+2X = -2

X(7X^2+11X+2) = -2

Unless there are typos in your equation, this as much as I can do.

I hope this helps. Thanks for asking.

Thank you very much!!

Thank You!!!

"Helpless again", see how the lack of proper brackets can wreck a question.
PsyDAG followed the order of operation exactly the way you typed it, and it led to a point where we cannot solve the equation.
Had you typed it the way it was probably meant to be...

5/(x+6) + 2/(x^2 + 7x + 6) = 3/(x+1)
the second term factors at the bottom
5/(x+6) + 2/((x+1)(x+6)) = 3/(x+1)

multiplying every term by (x+1)(x+6)...

5(x+1) + 2 = 3(x+6) now it's a little grade nine equation for
x=11/2