Okay. So i'm doing this project for my geometry class about different sports, soccer, baseball, basketball, bowling, golf, volleyball and pool. I have to find the surface area, volume, diameter, circumference, and radius of each of the balls. I got a circumference for each one and I know the formula for circumference is diameter*pi

How would I find the diameter if I only have the circumference?

And I think the formula for surface area, i need the one for a sphere. Is that T=4pi r^2? And then is the volume V=4/3 pi r3

thanks for the help :]

you have the right formulas.

If you have the circumference of the ball, then, if you consider a cross-section of the ball, you are looking at the circumference of a circle.

so, if for example the circumference is 65 cm, then
65 = 2pi*r
r=65/(2pi)
r= 10.3

once you have the radius, just plug it into the volume and surface area formulas, I am sure you know what to do.

Welp. That was posted in 2007... did u ever get your help? xD

Hopefully, they did get their help.

To find the diameter if you have the circumference, you can use the formula: diameter = circumference / pi.

For example, if you have a circumference of 65 cm, you can calculate the diameter by dividing 65 by pi (approximately 3.14159).

diameter = 65 / 3.14159 = 20.65 cm

So, the diameter of the ball in this example is approximately 20.65 cm.

Now let's move on to the formulas for surface area and volume. You are correct, the formula for the surface area of a sphere is:

Surface Area (S) = 4 * pi * radius^2

And the formula for the volume of a sphere is:

Volume (V) = (4/3) * pi * radius^3

To calculate the surface area and volume, you can use the radius you calculated earlier (10.3 cm in this example).

Surface Area = 4 * pi * (10.3)^2 = 1328.73 cm^2

Volume = (4/3) * pi * (10.3)^3 = 4499.36 cm^3

So, for this particular ball, the surface area is approximately 1328.73 cm^2 and the volume is approximately 4499.36 cm^3.

You can repeat these steps for each of the balls to find their respective diameters, surface areas, and volumes.