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January 28, 2015

January 28, 2015

Posted by **wi** on Monday, May 21, 2007 at 2:13pm.

I am stuck on this question. y=x^2+4x and y^2= 25x^2+20x+3

how many of the solutions are real? and how many of the real roots are positive and how many are negative?

thank you for any suggestions

I suggest you solve for the roots.

y=x(x+4) At y=0, what are the roots?

Y= (5x+3)(5x+1)

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