Write the equation of the line passing through the given pair of points. Write your result in slope-intercept form.
(-1,3) and (4,-2)
Show equation
I will be happy to critique your work on this.
y-3=1(x+1)
y-3=1x+-1
y=x+2?
Let's find the equation of the line passing through the points (-1,3) and (4,-2) using the slope-intercept form.
Step 1: Find the slope (m) of the line.
The slope (m) can be found using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates (-1,3) and (4,-2), we can substitute the values into the formula:
m = (-2 - 3) / (4 - (-1))
m = (-2 - 3) / (4 + 1)
m = -5 / 5
m = -1
Step 2: Use the slope-intercept form (y = mx + b) and substitute the slope (m) and one of the points (x1, y1) to find the y-intercept (b).
Using the coordinates (-1,3):
3 = -1(-1) + b
3 = 1 + b
b = 3 - 1
b = 2
Step 3: Substitute the found values of m and b into the slope-intercept form (y = mx + b).
The equation will be:
y = -1x + 2
Therefore, the equation of the line passing through the points (-1,3) and (4,-2) in slope-intercept form is y = -x + 2.