# caculus

posted by
**jimmy** on
.

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=11-x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width=? Height=?

Area= height*width=y(2x)

Area=(11-x^2)(2x)

solve for dArea/dx, set to zero, solve for x. Width will be 2x, height y.

ty very much!