Posted by **jimmy** on Saturday, May 19, 2007 at 11:55pm.

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=11-x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width=? Height=?

Area= height*width=y(2x)

Area=(11-x^2)(2x)

solve for dArea/dx, set to zero, solve for x. Width will be 2x, height y.

ty very much!

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