Saturday
April 19, 2014

Homework Help: Chemistry

Posted by Tri on Saturday, May 19, 2007 at 6:57pm.

In a experiment to determine the molecular weight and the Ka for ascorbic acid (vit. c.) a student dissolved 1.3713g of the monoprotic acid in water to make 50 mL of solution. The pH was monitored throughout the titration. The equivalence point was reached when 35.23 mL of the base was added.

1) Calculate the molecular mass of ascorbic acid.

2) When 20mL of NaOH was added during the titration the pH was 4.23. Calculate the Ka for ascorbic acid.

3) What was the pH at the equivalence point?

To find molecular mass of an acid in a titration experiment, one must use this formula:

Ca*Va=Cb*Vb
therefore
Ca=(Cb*Vb)/Va

C=concentration (molarity)
V=volume
a=acid
b=base

Thanks for the answer, but I haven't yet seen that formula yet, can you tell me the name for the formula?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - Ascorbic acid is a weak organic acid also known as vitamin C. A ...
NEED HELP WITH CHEMISTRY HW - Ascorbic acid (vitamin C) is a diprotic acid ...
Chemistry Acid Question Ka - Enough of a monoprotic acid is dissolved in water ...
AP Chemistry - How many grams of benzoic acid, a monoprotic acid with a Ka=6....
Chem - Aspirin (acetylsalicylic acid, ) is a weak monoprotic acid. To determine ...
urgent i need help within an hour! - Ascorbic acid (vitamin C, C6H8O6) is a ...
chemisrty - Q1) A solution of ascorbic acid (C6H8O6, Formula mass = 176 g/mol) ...
chemistry - .0900g of unknown acid(diproctic acid) with empirical formular(CHO2...
Chemistry - Enough of a monoprotic acid is dissolved in water to produce a 1.47 ...
Chemistry - Enough of a monoprotic acid is dissolved in water to produce a 0....

Search
Members