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December 19, 2014

December 19, 2014

Posted by **claudia** on Friday, May 18, 2007 at 7:56am.

A surveyor, standing at an observation point on a cliff top of a height 300m above sea level, can see a boat and a bouy out at sea, both directly in front of him. He measures the angle from the top of the cliff to the bouy Y as 27 degrees and the angle from the top of the cliff to the boat Z as 18 degrees

make a diagram and put in all your information.

You should see two right-angled triangles.

tan 27 = 300/x, where x is the distance from the base of the cliff to the bouy is your first calculation.

if y is the distance from the base of the cliff to the boat, then tan 18 = 300/y

evaluate x and y, take y-x and state the answer to 2 significant figures.

Let me know what you get.

Reiny thank you so much for helping me.

Is it 55 ??

no, from tan 27 = 300/x

I got x= 300/tan27 = 588.8

from tan 18 = 300/y I got

y=300/tan 18 = 923.3

then the difference is 923.3-588.8

=334.5

which is 330 m to 2 significant figures.

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