What is the period of this function? - Maths?

y = 5+3sin (pie t divided by 3 + pie divided 2)

by definition the period is 2pi/k where k is the coefficient of the "angle"

so divide 2pi by pi/3 and simplify, hope you get 6

To find the period of the function y = 5 + 3sin((πt/3) + π/2), we can use the formula for the period of the sine function.

The general formula for the period of a sine function is given by 2π/k, where k is the coefficient of the "angle" or the term inside the sine function.

In this case, the coefficient of the "angle" is (π/3). Therefore, the period of the function is:

Period = 2π / (π/3)

To simplify this expression, we can multiply by the reciprocal of π/3, which is 3/π:

Period = 2π / (π/3) * (3/π)

Simplifying further by canceling out the π:

Period = 2 * 3

Period = 6

Therefore, the period of the given function is 6.