What is the period of this function? - Maths?
y = 5+3sin (pie t divided by 3 + pie divided 2)
by definition the period is 2pi/k where k is the coefficient of the "angle"
so divide 2pi by pi/3 and simplify, hope you get 6
To find the period of the function y = 5 + 3sin((πt/3) + π/2), we can use the formula for the period of the sine function.
The general formula for the period of a sine function is given by 2π/k, where k is the coefficient of the "angle" or the term inside the sine function.
In this case, the coefficient of the "angle" is (π/3). Therefore, the period of the function is:
Period = 2π / (π/3)
To simplify this expression, we can multiply by the reciprocal of π/3, which is 3/π:
Period = 2π / (π/3) * (3/π)
Simplifying further by canceling out the π:
Period = 2 * 3
Period = 6
Therefore, the period of the given function is 6.