Friday
July 25, 2014

Homework Help: intro cal

Posted by Emma on Friday, May 18, 2007 at 7:46am.

the first 3 term of a geometric progression are
k-4, 2k-4, 4k+4.

what is the value of k?

can someone help please!

in any geometric progression any term divided by its previous term gives you the common ratio, so ....

(2k-4)/(k-4) = (4k+4)/(2k-4)

cross-multiply and proceed.
I comes out nice, the square term cancels.

how do i cross multiply this?i get confused easiy when doing cross multiply in division...

(2k-4)(2k-4) = (k-4)(4k+4)
4k^2 - 16k + 16 = 4k^2 - 12k - 16
-4k = -32
k=8

ooh so you times it by the opposite!silly me...
Thank you soo much!!

yes, in general

a/b = c/d -----> bc = ad

try it with equivalent fractions

we know 2/3 = 10/15
then 2*15 = 3*10 ...true!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Geometric progression - The second term of a geometric progression is 12 more ...
Maths - 1..The first 2 terms of a geometric progression are the same as the ...
math - 1) If the number 1,1/3,1/9, are terms of Geometric progression. Find its ...
Math (Geometric Progression) - 5 distinct positive reals form an arithmetic ...
Math Algebra - The first term of a geometric progression is more than the third ...
Math - 5 distinct positive reals form an arithmetic progression. The 1st, 2nd ...
GP Caluculus - The third term of a geometric progression is 16. The sum of the ...
GP Caluculus - The third term of a geometric progression is 16. The sum of the ...
GP Caluculus - The third term of a geometric progression is 16. The sum of the ...
Geometric Sequence - The product of the first five terms of a geometric ...

Search
Members